From ef72f1bf707dca363cdab84da91e2acfaef8f276 Mon Sep 17 00:00:00 2001
From: Ammar Alakkad <am.alakkad@gmail.com>
Date: Mon, 30 Dec 2024 16:03:57 +0000
Subject: [PATCH] Fix ObsidianFlavoredMarkdown source link (#1694)
---
docs/features/Latex.md | 11 +++++++++++
1 files changed, 11 insertions(+), 0 deletions(-)
diff --git a/docs/features/Latex.md b/docs/features/Latex.md
index b2bdb2d..fdc9d27 100644
--- a/docs/features/Latex.md
+++ b/docs/features/Latex.md
@@ -39,6 +39,17 @@
\end{bmatrix}
$$
+$$
+\begin{array}{rll}
+E \psi &= H\psi & \text{Expanding the Hamiltonian Operator} \\
+&= -\frac{\hbar^2}{2m}\frac{\partial^2}{\partial x^2} \psi + \frac{1}{2}m\omega x^2 \psi & \text{Using the ansatz $\psi(x) = e^{-kx^2}f(x)$, hoping to cancel the $x^2$ term} \\
+&= -\frac{\hbar^2}{2m} [4k^2x^2f(x)+2(-2kx)f'(x) + f''(x)]e^{-kx^2} + \frac{1}{2}m\omega x^2 f(x)e^{-kx^2} &\text{Removing the $e^{-kx^2}$ term from both sides} \\
+& \Downarrow \\
+Ef(x) &= -\frac{\hbar^2}{2m} [4k^2x^2f(x)-4kxf'(x) + f''(x)] + \frac{1}{2}m\omega x^2 f(x) & \text{Choosing $k=\frac{im}{2}\sqrt{\frac{\omega}{\hbar}}$ to cancel the $x^2$ term, via $-\frac{\hbar^2}{2m}4k^2=\frac{1}{2}m \omega$} \\
+&= -\frac{\hbar^2}{2m} [-4kxf'(x) + f''(x)] \\
+\end{array}
+$$
+
> [!warn]
> Due to limitations in the [underlying parsing library](https://github.com/remarkjs/remark-math), block math in Quartz requires the `$$` delimiters to be on newlines like above.
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